SOLUTION: x^1+x^2+x^3=0
2x^1-x^2-x^3=-3
x^1-x^2+x^3=0
Algebra.Com
Question 302770: x^1+x^2+x^3=0
2x^1-x^2-x^3=-3
x^1-x^2+x^3=0
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Are these linear systems of functions of x (, , and )?
If so, it doesn't look like there is a solution (no common intersection point for all three graphs).
.
.
.
Or are these , , and , three variables?
[A]=
[x]=
[b]=
Then
[A][x]=[b]
[x]=[A]inv[b]
.
.
det[A]=
[A]inv=
[x]=
.
.
.
RELATED QUESTIONS
x^3-x^2-x+1=0 (answered by nerdybill)
3^2x - 3^x+1 +2 =... (answered by Aldorozos,robertb)
(x-4)²+8=0
(x+2)²=3(x+2)
(2x-1)²=(x+1)²
2x(x+4)=(x-3)(x-3)
(answered by josgarithmetic)
(x-1)(x-2)(x-3)<0... (answered by lwsshak3)
(x^3-x)/(x+1)+(2x^2-2)/(x+1) (answered by jim_thompson5910)
2x+ x^1/2... (answered by Fombitz)
x-3/4-2x - 1/x-2 + 1 =... (answered by jim_thompson5910)
4(x - 3) - 2(x - 1) >... (answered by checkley71)
(x+3)^2(x+1)>0 (answered by Fombitz)