SOLUTION: How do I solve for both methods? directions:Slove the linear equations using both substitution and combination method. y=4x-6 3y=7-3x

Question 29875: How do I solve for both methods?
directions:Slove the linear equations using both substitution and combination method.
y=4x-6
3y=7-3x
Answer by Cintchr(481) (Show Source): You can put this solution on YOUR website!
and Substitute 4x-6 from the firt equation into the second.

distribute the 3
add 3x to both sides
add 18 to both sides
divid both sides by 15
reduce

plug x = 5/3 back into the first equation

change 6 to 18/3 (common denom)
subtract

solution : (5/3, 2/3)
now by elimination:
and we will deal with the first equation
solve for the form Ax+By=C
subtract 4x from both sides
multiply by -1 to make the x value positive
now solve the second equation so that it is in the same form
add 3x to both sides
now lets look at both equations stacked on ontop of the other.
4x - 1y = 6
3x + 3y = 7
if we multiply all parts of the first equation by three we get ...
12x - 3y = 18
3x + 3y = 7
looking at the y values .. they will cancel when we add the two equations and get ...
15x + 0y = 25 the y is gone now ...
15x = 25 divide both sides by 15
x = 25/15 or 5/3
substitute this back into ANY of the equations to find y
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