Solve by the addition method:
11x + 2y = -1
2x + 3y = 13
To eliminate the x's, we multiply thru each equation by numbers that will
cause the new coefficients of x to become equal in absolute value but
opposite in sign.
The least common multiple of coefficients of x, 11 and 2, is 22. Thus we
want to cause one of the coefficients of x to become +22 and the other -22.
To accomplish this we multiply the first equation thru by 2 and the second
equation by -11
22x + 4y = -2
-22x - 33y = -143
-----------------
Adding these vertically:
-29y = -145
y = 5
------------------------
11x + 2y = -1
2x + 3y = 13
The least common multiple of coefficients of y, 2 and 3, is 6. Thus we
want to cause one of the coefficients of x to become +6 and the other -6.
To accomplish this we multiply the first equation thru by 3 and the second
equation by -2
33x + 6y = -3
-4x - 6y = -26
-----------------
Adding these vertically:
29x = -29
x = -1
So the solution is (-1,5)
Edwin