# SOLUTION: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?.

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?.      Log On

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 Click here to see ALL problems on Linear-systems Question 274940: A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?.Found 2 solutions by josmiceli, dabanfield:Answer by josmiceli(9668)   (Show Source): You can put this solution on YOUR website! (1) (2) Substitute (1) into (2) hrs and, since mi Answer by dabanfield(803)   (Show Source): You can put this solution on YOUR website! A car travels from one town to another at a speed of 32 mph. If it had gone 4 mph faster, it could have made the trip in 1/2 hr less time. How far apart are the towns?. If the distance between towns is d and the time needed to travel at 32 mph is t then we have: d = 32*t or 1.) t = d/32 At the faster speed (32+4=36) it takes .5 hours less to travel the same distance so we have: d = 36*(t - 1/2) or 2.) d = 36*t - 18 From 1.) we know that t = d/32 so we can substitute d/32 for t in equation 2.) which gives us: d = 36*(d/32) - 18 d = (36/32)*d - 18 d = (9/8)*d - 18 (9/8)*d - d = 18 d/8 = 18 d = 18*8 = 144