SOLUTION: Here is my problem. The perimeter of the rectangle is 24 and the perimeter of the triangle is 23 Here are the sides of the rectangle: side 1- x side 2- 3y side 3- x side

Question 274439: Here is my problem.
The perimeter of the rectangle is 24 and the perimeter of the triangle is 23
Here are the sides of the rectangle:
side 1- x
side 2- 3y
side 3- x
side 4- 3y

here are the sides of the isosoles triangle:
side 1- x+1
side 2- x+y
side 3- y+6
Write a system of linear equations to represent this problem.
How would I do that?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Here is my problem.
The perimeter of the rectangle is 24 and the perimeter of the triangle is 23
Here are the sides of the rectangle:
side 1- x
side 2- 3y
side 3- x
side 4- 3y
-------------------
Equation:
1-x + 2-3y+3-x + 4-3y = 24
-2x -6y + 10 = 24
-2x - 6y = 14
x + 3y = -7
--------------------
here are the sides of the isosoles triangle:
side 1- x+1
side 2- x+y
side 3- y+6
Equation:
x+1 + x+y + y+6 = 23
2x + 2y + 7 = 23
2x + 2y = 16
x + y = 8
----------------------------
Write a system of linear equations to represent this problem.
x + 3y = -7
x + y = 8
----
Subtract the 2nd equation from the 1st:
2y = -15
y = -15/2
------
Since x + y = 8, substitute and solve for "x":
x -15/2 = 16/2
x = 31/2
-------------------
Cheers,
Stan H.
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