SOLUTION: The cost to run machine 1 for an hour is $2. During that hour, Machine 1 produces 240 bolts and 100 nuts. The cost to run machine 2 for an hour is $2.40. During that hour, Machine
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Question 272598: The cost to run machine 1 for an hour is $2. During that hour, Machine 1 produces 240 bolts and 100 nuts. The cost to run machine 2 for an hour is $2.40. During that hour, Machine 2 produces 160 bolts and 160 nuts. With a combined running time of no more that 30 hours, how long should each machine run to produce an order of at least 2080 bolts and 1520 nuts at the minimum operating cost?
I can't figure out the proper equations to graph.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The cost to run machine 1 for an hour is $2.
During that hour, Machine 1 produces 240 bolts and 100 nuts.
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The cost to run machine 2 for an hour is $2.40.
During that hour, Machine 2 produces 160 bolts and 160 nuts.
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With a combined running time of no more that 30 hours, how long should each machine run to produce an order of at least 2080 bolts and 1520 nuts at the minimum operating cost?
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Let "x" be machine 1 running time: x >= 0
Let "y" be machine 2 running time: y >= 0
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Objective Function: Cost = 2x + 2.40y
This is the function to be minimized
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Equations:
time: x + y = 7
bolts: 240x + 160y >=2080
nuts:: 100x + 160y >- 1520
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Solve equations/inequlities for y and graph.
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I guess you know the rest of the procedure
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Cheers,
Stan H.
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