SOLUTION: solve by eilimination 1)3x+7y =48 5x-7y= -32 2)-2x+3y =25 -2x+6y=58 3)3x+8y = 81 5x+6y=-39 4)8x+13y=179 2x-13y=-69

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Question 264711: solve by eilimination
1)3x+7y =48
5x-7y= -32
2)-2x+3y =25
-2x+6y=58
3)3x+8y = 81
5x+6y=-39
4)8x+13y=179
2x-13y=-69

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

I'll just do the 3rd one, the hardest one:



To eliminate the x's:

The coefficients of x are 3 and 5.
The least common multiple of 3 and 5 is 15. We want to
make one of the coefficients of x 15 and the other one
-15.  To do that we multiply the first equation through
by 5 and the second one through by -3:



Add the two equations term by term
 





Go back to the original system:



To eliminate the y's:
The coefficients of y are 8 and 6.
The least common multiple of 8 and 6 is 24. We want to
make one of the coefficients of y 24 and the other one
-24.  To do that we multiply the first equation through
by 3 and the second one through by -4:



Add the two equations term by term
 






Edwin

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