SOLUTION: how to solve using substitution
y=2x-3 and y=-x-3
Algebra.Com
Question 261879: how to solve using substitution
y=2x-3 and y=-x-3
Found 3 solutions by drk, richwmiller, solver91311:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
To solve using substitution, we need to solve an equation for y. We already have that in the two given equations:
(i)
(ii)
set them equal to get
(iii)
add x to both sides to get
(iv)
add 3 to both sides to get
(v)
so,
x = 0
and
y = -3
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
take -x-3 and substitute it for the y of the first equation to get
-x-3=2x-3
add x to both sides
-3=3x-3
add 3 to both sides
0=3x
x=0
y=-3
(0,-3)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You have two equations each of which describe the value of 
in terms of 
.
Start with the first equation:
In place of the in that equation, substitute the expression in from the other equation:
Now just solve the single equation in one variable. Once you have a value for the variable, substitute that back into either equation to determine the value for . The solution set will be a single ordered pair of the form )
such that the coordinates will make true statements out of either given equation.
John
RELATED QUESTIONS
How would you solve y=-2x+3 and x+y=4? Using the Substitution... (answered by TimothyLamb)
how to solve this using substitution and check
x-6y+4=0
y= -3... (answered by stanbon)
How to solve using the substitution method
x^2+y=5
x-y+3=0
(answered by amarjeeth123)
How do I solve this by using substitution? y=2x+3 and... (answered by EdenWolf)
How do I solve this system using the substitution method?
x-y=3... (answered by Alan3354)
please help
Use substitution to solve for x and y
3x - y = 3
y = 2x -... (answered by funmath)
solve by substitution: x-2y=-3 and... (answered by math_freak)
Using substitution to find the point (x,y)
y=3-2x... (answered by jim_thompson5910)
8) how to solve y=x+3 with the substitution of... (answered by rfer)