SOLUTION: suppose M is between L and N use segment Additing postulate to solve for the variable then find lengths of line LM, line MN and line LN. LM= 3x+8 MN= 2x-5 LN= 23

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Question 261876: suppose M is between L and N use segment Additing postulate to solve for the variable then find lengths of line LM, line MN and line LN.
LM= 3x+8
MN= 2x-5
LN= 23
Found 3 solutions by drk, solver91311, checkley77:
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website!
M is between L and N.
LM + MN = LN by segment addition postulate.
So,

combine like terms to get

subtract 3 to get

divide by 5 to get

LM = 20
MN = 3

Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!

The segment addition principle says that if a segment is divided into a number of smaller segments then I can add the measures of all of the small segments to get the measure of the original segment. In other words:

Substituting the given values we get:

Solve the equation for .

John

Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website!
LM= 3x+8
MN= 2x-5
LN= 23
3x+8+2x-5=23
5x=23-8+5
5x=20
x=20/5
x=4
LM=3*4+8=12+8=20
MN=2*4-5=8-5=3
PROOF:
20+3=23
23=23