SOLUTION: Hi! I need help with this direct variation equation.
It says If y=4 when x=2, find y when x=16.
How do you solve this?
Thanks -Drea
Algebra.Com
Question 254857: Hi! I need help with this direct variation equation.
It says If y=4 when x=2, find y when x=16.
How do you solve this?
Thanks -Drea
Found 2 solutions by nerdybill, richwmiller:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
It says If y=4 when x=2, find y when x=16.
How do you solve this?
.
In "direct variation" the relation is:
y = kx
where
k is a constant
.
The problem gives you the fact that:
If y=4 when x=2
Use this to discover what k is:
Plugging what we know into:
y = kx
4 = k(2)
4/2 = k
2 = k
.
So, our relation is:
y = 2x
To find y when x=16 simply plug x into:
y = 2x
y = 2(16)
y = 32
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
I looked this up and they don't consider it direct variation if b does not equal zero so b always has to equal zero for direct variation
y=mx is the equation that governs direct variation.
4=m*2
If m=2
y=2*16
y=32
RELATED QUESTIONS
I need help with this problem
In Exercises 14-29, y varies directly as x. Find the... (answered by stanbon)
This has to do with direct, indirect, and joint variation. Sorry but I couldn't find it... (answered by Mathtut)
"Tell whether this equation represents a direct variation. If so, identify the constant... (answered by rothauserc)
how do i solve:
if y=2 2/3 when x=1/4 find y when x=1 1/8
im not sure what category (answered by Cromlix)
in direct variation if y varies directly with x:
find the equation for the direct... (answered by drk)
Hi! I need help with this equation. The directions read determine if each equation is a... (answered by richwmiller)
how do i solve direct variation Y=15 when... (answered by Fombitz)
please help.. they are indirect and direct variations, please show work.. asap
3.If y... (answered by RAY100)
I need to write an equation for the direct variation then fin the value to the following: (answered by josgarithmetic)