SOLUTION: A child is holding nickels, dimes and quarters in his hand that add up to $4.95 There are the same number of dimes and quarters but there are twice as many nickels as dimes. How m
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-> SOLUTION: A child is holding nickels, dimes and quarters in his hand that add up to $4.95 There are the same number of dimes and quarters but there are twice as many nickels as dimes. How m
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Question 253612: A child is holding nickels, dimes and quarters in his hand that add up to $4.95 There are the same number of dimes and quarters but there are twice as many nickels as dimes. How many nickels are there? Found 2 solutions by richwmiller, drk:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! 25q+10d+5n=495
d=q
n=2d
d=11
q=11
n=22
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You can put this solution on YOUR website! There are a few equations here. Let N = nickel, D = dime, and Q = quarter.
First, the money equation:
(i)
Second,
(ii)
Third,
(iii)
We want to get everything into the same variable. Turn everything into D. From substitution of (ii) and (iii) into (i), we get
(iv)
Solving for D, we get
(v)
dividing by 45, we get
and
(