SOLUTION: I am having trouble with this problem. SOLVE THIS SYSTEM OF EQUATIONS, WHEN POSSIBLE... x+y+z=4 x-y+2z=8 2x+y-z=3 I used the elimination method and broke this down into

Question 24526: I am having trouble with this problem.
SOLVE THIS SYSTEM OF EQUATIONS, WHEN POSSIBLE...
x+y+z=4
x-y+2z=8
2x+y-z=3
I used the elimination method and broke this down into two equations with only two variables. I try to eliminate another variable, but cannot do it! HELP PLEASE!!
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve:
1)
2)
3) Add equations 1) and 2) to get:
4) Add equations 2) and 3) to get:
5) Multiply equation 5) by 3 to get:
6) Now subtract equation 4) from equation 6) to get:
7) Divide both sides by 7.
Substitute this into equation 5) and solve for z.

Subtract 9 from both sides.
Finally, substitute x=3 and z=2 into equation 1) and solve for y.

Subtract 5 from both sides.

Solution:
x = 3
y = -1
z = 2
Check by substituting these values into the three equations, 1), 2), and 3)
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