SOLUTION: Thanks for helping me sole the equations. I sent an equation with error.
this is the correct equations.
Solve for A and B in the following problem.
4A+B=16, 2A+3B=24
Tha
Algebra.Com
Question 2410: Thanks for helping me sole the equations. I sent an equation with error.
this is the correct equations.
Solve for A and B in the following problem.
4A+B=16, 2A+3B=24
Thank you!
Answer by gsmani_iyer(201) (Show Source): You can put this solution on YOUR website!
4a + b = 16 ... (1)
2a + 3b = 24 ... (2)
Eq.(1)*3, we get
12a + 3b = 48 ... (3)
Eq.(3)-(2)
10a = 24
so, a = 2.4. By substituting this value of a in eq.no.1, we get
4*2.4 + b = 16
b = 16 - (4*2.4) i.e = 16 - 9.6
b = 6.4
a = 2.4; b = 6.4; Answer.
Is it clear now?
gsm
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