SOLUTION: {{{n^3 -3n^2 + 2n = 210}}}

Question 23624:
Found 2 solutions by kviji_85, Earlsdon:
Answer by kviji_85(2) (Show Source): You can put this solution on YOUR website!
{n^3 -3n^2 + 2n = 210}
n(n^2-3n+2)=210
n(n^2-2n-n+2)=210
n(n(n-2) - (n-2)) = 210
n(n-1)(n-2)=10

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for n:
Subtract 210 from both sides of the equation.
Factor.
Apply the zero product principle.
and/or
If then n = 7 This is one of the three roots.
If Use the quadratic formula to solve:

or
or
The three roots are:

Here's the graph of the equation:
)
RELATED QUESTIONS
Factor n^4 - 2n^3 -... (answered by nerdybill)
(n^4-2n^3-3n^2+7n-2)/(n-2) (answered by stanbon)
(n+2n)=3n (answered by Alan3354)
Please help me solve this equation. 2(3n(n-2)) = 3(2n(n-1)+12 (answered by ikleyn)
(3n+2)(n+3) (answered by tommyt3rd)
Simplify and state restrictions {{{ (n^2+3n+2)/(n^2+5n+6)-(2n)/(n+3) }}} Thank... (answered by Boreal)
Please solve and state restrictions {{{(n^2+3n+2)/(n^2+5n+6)}}} minus... (answered by Boreal)
prove using mathematical induction: 1. 1^4 + 2^4 + 3^4 + ... + n^4 =... (answered by math_helper,robertb)
n^2-2n-3 (answered by checkley79)