# SOLUTION: I have two questions I just don't get them. Solve the system of linear equations by graphing: x+2y=5 x-y=2 that is the first on

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: I have two questions I just don't get them. Solve the system of linear equations by graphing: x+2y=5 x-y=2 that is the first on      Log On

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 Question 23376: I have two questions I just don't get them. Solve the system of linear equations by graphing: x+2y=5 x-y=2 that is the first one the second one is: 4x-y=6 3x+y=1 these are very hard for me please helpAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!SECOND PROBLEM IS SHOWN BELOW. ******************************************************************************** SOLVE BY GRAPHING MEANS DRAW THE GRAPHS AND FIND THE 2 GRAPHS OF 2 EQUATIONS CUT EACH OTHER .THAT IS THE SOLUTION.LET ME SHOW YOU THE SECOND PROBLEM. 4X-Y=6..OR...4X-6=Y..... 3X+Y=1...OR....Y=1-3X......... LET X=...........................0......1......2........3.........4......ETC.. Y=4X-6..IN FIRST EQN........-6......-2.....2........6.........10.......ETC Y=1-3X..IN SECOND EQN.......1.......-2.....-5.......-8........-11......ETC THE GRAPHS WILL LOOK LIKE THIS WE FIND THAT THE TWO GRAPHS ARE CUTTING AT X=1 AND Y=-2.HENCE THAT IS THE SOLUTION..YOU CAN CHECK BACK EQN.I.....4X-Y=4*1-(-2)=4+ 2 = 6 ..OK EQN.II.....3X+Y=3*1+(-2)=3-2=1........OK. ******************************************************************************* Solve the system of linear equations by graphing: x+2y=5.. OR 2Y=5-X..OR Y=(5-X)/2 x-y=2... OR Y=X-2 that is the first one the second one is: 4x-y=6 3x+y=1 SOLVE BY GRAPHING MEANS DRAW THE GRAPHS AND FIND THE 2 GRAPHS OF 2 EQUATIONS CUT EACH OTHER .THAT IS THE SOLUTION.LET ME SHOW YOU THE FIRST PROBLEM. THEN YOU CAN DO SECOND PROBLEM THE SAME WAY LET X=.........................0......1......2........3.........4......5....ETC. Y=(5-X)/2..IN FIRST EQN........5/2....2......3/2......1.........1/2....0...ETC Y=(X-2).....IN SECOND EQN.......-2....-1......0........1.........2......3...ETC THE GRAPHS WILL LOOK LIKE THIS WE FIND THAT THE TWO GRAPHS ARE CUTTING AT X=3 AND Y=1.HENCE THAT IS THE SOLUTION..YOU CAN CHECK BACK EQN.I.....X+2Y=3+2*1=3+2=5..OK EQN.II.....X-Y=3-1=2........OK.