SOLUTION: Systems of Equations A chemist has two solutions of hydrochloric acid in stock: a 50% solution and an 80% solution. How many of each should she mix to obtain 100 milliliters of

SOLUTION: Systems of Equations A chemist has two solutions of hydrochloric acid in stock: a 50% solution and an 80% solution. How many of each should she mix to obtain 100 milliliters of

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Question 225656: Systems of Equations
A chemist has two solutions of hydrochloric acid in stock: a 50% solution and an 80% solution. How many of each should she mix to obtain 100 milliliters of a 68% solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.80X+.50(100-X)=.68*100
.80X+50-.50X=68
.30X=68-50
.30X=18
X=18/.30
X=60 ML OF 80% SOLUTION IS USED.
100-60=40 ML. OF 50% SOLUTION IS USED.
PROOF:
.80*60+.5*40=.68*100
48+20=68
68=68
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