SOLUTION: Hello, Please help me with this quesion... "Solve each system of equalities" {2x+y=8 -x+3y=10 I would appreciate it, Thanks

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Hello, Please help me with this quesion... "Solve each system of equalities" {2x+y=8 -x+3y=10 I would appreciate it, Thanks      Log On


   

Question 222826: Hello, Please help me with this quesion...
"Solve each system of equalities"
{2x+y=8
-x+3y=10
I would appreciate it,
Thanks
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Hello, Please help me with this quesion...
"Solve each system of equalities"

2x+y=8
-x+3y=10

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++2%5Cx+%2B+1%5Cy+=+8%2C%0D%0A++++-1%5Cx+%2B+3%5Cy+=+10+%29%0D%0A++We'll use substitution. After moving 1*y to the right, we get:
2%2Ax+=+8+-+1%2Ay, or x+=+8%2F2+-+1%2Ay%2F2. Substitute that
into another equation:
-1%2A%288%2F2+-+1%2Ay%2F2%29+%2B+3%5Cy+=+10 and simplify: So, we know that y=4. Since x+=+8%2F2+-+1%2Ay%2F2, x=2.

Answer: system%28+x=2%2C+y=4+%29.



I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J