SOLUTION: solve each system of equations by using substitution 2x+y=4 3x+2y=1 my work so far was 3x+2(2x+4)=1 and then 3x+4x+8=1 and then you add the x's so 7x+8=1 Now what?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: solve each system of equations by using substitution 2x+y=4 3x+2y=1 my work so far was 3x+2(2x+4)=1 and then 3x+4x+8=1 and then you add the x's so 7x+8=1 Now what?       Log On


   

Question 220396: solve each system of equations by using substitution
2x+y=4
3x+2y=1
my work so far was 3x+2(2x+4)=1 and then 3x+4x+8=1 and then you add the x's so 7x+8=1
Now what?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
2x+y=4 ___ y = 4 - 2x

substituting ___ 3x + 2(4 - 2x) = 1 ___ 8 - x = 1 ___ x = 7

substituting ___ y = 4 - 2(7) ___ y = -10