SOLUTION: find the vertex of the parabola y= x^2-2x-1 vertex (?,?)

Question 212969: find the vertex of the parabola
y= x^2-2x-1
vertex (?,?)
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Find the vertex of the parabola

vertex (?,?)

Let's graph this parabola:

Try this set of x=-2, -1, 0, 1, 2 and substitute into parabola equation.

For example, x=-2, y=(-2)^2-2(-2)-1= 4+4-1=7 point on graph is (-2,7)

One more and then you try, x=-1, y=(-1)^2-2(-1)-1=-1 point on graph is (-1,-1)

Based on the graph the vertex is (1, -2)

Note when we substitute x=1 in

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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