SOLUTION: This problem in extra work but i am confused. If anyone can help thanks. Solve algebraically, using the five step method. Show all steps. The area of a rectangle in 525cm^2 Fi

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: This problem in extra work but i am confused. If anyone can help thanks. Solve algebraically, using the five step method. Show all steps. The area of a rectangle in 525cm^2 Fi      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 211087: This problem in extra work but i am confused. If anyone can help thanks.
Solve algebraically, using the five step method. Show all steps.
The area of a rectangle in 525cm^2 Find the dimensions of a rectangle if the ratio of the length to the width is 7:3
Answer by ankor@dixie-net.com(15649) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle in 525cm^2
Find the dimensions of a rectangle if the ratio of the length to the width is 7:3
:
let x = the multiplier
then
7x = the length
and
3x = the width
:
Area equation (L*W)
7x * 3x = 525
21x^2 = 525
Divide both sides by 21, results
x^2 = 25
x = 5 is the multiplier
then
5*7 = 35 is the length
and
5*3 = 15 is the width
;
Check; 35 * 15 = 525