# SOLUTION: This problem in extra work but i am confused. If anyone can help thanks. Solve algebraically, using the five step method. Show all steps. The area of a rectangle in 525cm^2 Fi

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: This problem in extra work but i am confused. If anyone can help thanks. Solve algebraically, using the five step method. Show all steps. The area of a rectangle in 525cm^2 Fi      Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Mathway solves algebra homework problems with step-by-step help!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Question 211087: This problem in extra work but i am confused. If anyone can help thanks. Solve algebraically, using the five step method. Show all steps. The area of a rectangle in 525cm^2 Find the dimensions of a rectangle if the ratio of the length to the width is 7:3Answer by ankor@dixie-net.com(16523)   (Show Source): You can put this solution on YOUR website!The area of a rectangle in 525cm^2 Find the dimensions of a rectangle if the ratio of the length to the width is 7:3 : let x = the multiplier then 7x = the length and 3x = the width : Area equation (L*W) 7x * 3x = 525 21x^2 = 525 Divide both sides by 21, results x^2 = 25 x = 5 is the multiplier then 5*7 = 35 is the length and 5*3 = 15 is the width ; Check; 35 * 15 = 525