# SOLUTION: please help me !! I am trying to help my son with an algebra word problem and I do not remember how to do this type of algebraic equation. I do remember: Time = Distance divid

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: please help me !! I am trying to help my son with an algebra word problem and I do not remember how to do this type of algebraic equation. I do remember: Time = Distance divid      Log On

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 Click here to see ALL problems on Linear-systems Question 210517: please help me !! I am trying to help my son with an algebra word problem and I do not remember how to do this type of algebraic equation. I do remember: Time = Distance divided by Rate . We have filled in the variables but that is as far as we got. Thanks, here is the question..... Fastball thrown by.....travels at a speed of 145km/hr toward the batter who is 18.3 meters away. How long does it take the baseball to travel this distance. Distance divided by Rate = Time 18.3m 145km/hr = t Found 2 solutions by checkley77, stanbon:Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!D=RT or T=D/R T=18.3 /145,000 (THERE ARE 1,000 METERS IN A KM) T=.0001262 HRS. or .007572 min. or .4543 SEC. Answer by stanbon(57953)   (Show Source): You can put this solution on YOUR website!Fastball thrown by.....travels at a speed of 145km/hr toward the batter who is 18.3 meters away. How long does it take the baseball to travel this distance. ---------------------------------------- Distance divided by Rate = Time 145 km/hr = 145000 meters per hour ---------------------------------------- Equation: 18.3m / 145000 m/hr = 0.0001262...hrs ---- Change to seconds: 0.0001262 hrs = 0.0001262*3600 seconds = 0.4543 seconds ============================================================ Cheers, Stan H.