SOLUTION: 2x-3y+2z=-1 x+2y=-5 2x-y+7z=-8 the answer says that it should be 6,1,7 but i can't figure out how they got those answers. Please Help!

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: 2x-3y+2z=-1 x+2y=-5 2x-y+7z=-8 the answer says that it should be 6,1,7 but i can't figure out how they got those answers. Please Help!       Log On


   



Question 210102: 2x-3y+2z=-1
x+2y=-5
2x-y+7z=-8
the answer says that it should be 6,1,7 but i can't figure out how they got those answers. Please Help!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Are you sure that the answer provided is (6,1,7)? If this is what the book is telling you, then it is wrong. Why? The ordered triple (6,1,7) means that x=6, y=1 and z=7. These values must satisfy all three equations.


However, if we pick the second equation and plug in the given values, we get:

6%2B2%281%29=-5

6%2B2=-5

8=-5

which is clearly NOT true. So either the book has the wrong answer, or there's a typo in the problem. Either way, I'd double check everything.