SOLUTION: -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x
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-> SOLUTION: -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x
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Question 208616: -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
my answer came out to negative one but my teacher marked that problem as wrong too!i solved the top part which is everything before /x in my TI calculator and then divided it by x which equals -4
and still got the answer wrong can you help me??? Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
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If that's not what you meant, you need to add parentheses to make it clear.
=
= (-4*-4*(1/2)/(-2) + 12*(1/4)/(-4)
= 8/(-2) + 3/(-4)
= 16/(-4) + 3/(-4)
= 19/(-4)
= -19/4
You can put this solution on YOUR website! -12xz/(3y)+12z (squared)/x
x=-4 y=-2 z=1\2
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Substitute:
-12(-4)(1/2)/(3*-2) + 12*(1/2)^2 /(-4)
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24/(-6) + 12*(1/4)/-4
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Question: It is hard to tell what the "x" is the denominator of.
So I'm just going to leave it there. Hopefully you know what it
is deviding.
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= -4 + 3/(-4)
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Cheers,
Stan H.
PS: Reply to stanbon@comcast.net as the algebra.com
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