# SOLUTION: the perimeter of a rectangle is twice the sum of its length and its width. The perimeter is 28 meters and it's length is 2 meters more than twice it's width. What is it's length?

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Question 204102: the perimeter of a rectangle is twice the sum of its length and its width. The perimeter is 28 meters and it's length is 2 meters more than twice it's width. What is it's length?
Found 2 solutions by ichudov, MathTherapy:
You can put this solution on YOUR website!
use L for length and W for width:
Perimeter is: 2*L + 2*W = 28.
Length is 2 meters more than twice the width: L = 2*W+2.
Use the above for length in the perimeter:
2*(2*W+2) + 2*W = 28.
Solved by pluggable solver: EXPLAIN simplification of an expression

 Here's what you tried: This is an equation! Solutions: W=4. Graphical form: Equation was fully solved.Text form: 2*(2*W+2)+2*W=28 simplifies to 0=0Cartoon (animation) form: For tutors: `simplify_cartoon( 2*(2*W+2)+2*W=28 )` If you have a website, here's a link to this solution.

### DETAILED EXPLANATION

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Eliminated similar terms , replacing them with
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Solved linear equation equivalent to 6*W-24 =0
It becomes .
Result:
This is an equation! Solutions: W=4.

### Universal Simplifier and Solver

Done!

So, width = 4.
Since length = 2*W+2, length = 2*4+2 = 10.
Answer: Width = 4, length = 10.

You can put this solution on YOUR website!

Perimeter of a rectangle = twice its width + twice its length

Let width be w

Since length is 2 more than twice its width, then length = 2w + 2

2w + 2(2w + 2) = 28

2w + 4w + 4 = 28

6w = 24

w = 4

Since width is 4, then length is 2(4) + 2 =