SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1

Question 198244This question is from textbook
: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? This question is from textbook

Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let D = no of Dimes, and N = no of Nickels
.
1) .1 D + .05 N = 5.65
.
2) .1(2D) +.05( N+8) = 10.45
.
or .2D +.05N +.40 =10.45
.
or .2D +.05N = 10.05
.
substract 2) - 1)
.
.1D = 4.40
.
D = 44
.
Subst in 1) .1(44) + .05 N = 5.65
.
4.4 + .05 N = 5.65
.
.05 N = 1.25
.
N = 25
.
check,,1) .1(44) + .05(25) = 5.65,,,,ok
2) .1(88) + .05(33) = 10.45,,, ok
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