SOLUTION: How do you solve this linear system with substitution? 8x+3y=0 -x-9y=92 All I have got to is... x=-9y-92 3y(-9y-92)=0 -6y-92=0 -6y=92 I dont think I did it right?

Question 186085This question is from textbook Algebra 1
: How do you solve this linear system with substitution?
8x+3y=0
-x-9y=92
All I have got to is...
x=-9y-92
3y(-9y-92)=0
-6y-92=0
-6y=92
I dont think I did it right?? This question is from textbook Algebra 1

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
(1)
(2)
Subtract from both sides of (1)
(1)
Divide both sides by
(1)
Multiply the right side by
(1)
Substitute this in (2)
(2)
(2)
(2)
(2)
(2)
And, from
(1)
(1)
(1)
(1)
check answers:
(1)
(1)
OK
(2)
(2)
(2)
OK
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