SOLUTION: Please Help.
Use elimination to solve each system of equations.
X+4Y=11 X-6Y=11
Algebra.Com
Question 182608: Please Help.
Use elimination to solve each system of equations.
X+4Y=11 X-6Y=11
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given system of equations:
Multiply the both sides of the first equation by -1.
Distribute and multiply.
So we have the new system of equations:
Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:
Group like terms.
Combine like terms.
Simplify.
Divide both sides by to isolate .
Reduce.
------------------------------------------------------------------
Now go back to the first equation.
Plug in .
Multiply.
Remove any zero terms.
Divide both sides by to isolate .
Reduce.
So our answer is and .
Which form the ordered pair
.
This means that the system is consistent and independent.
Notice when we graph the equations, we see that they intersect at
. So this visually verifies our answer.
Graph of (red) and (green)
RELATED QUESTIONS
Use algebra to solve this system of equations:
3x = -26 + 4y and x-6y... (answered by waynest)
Need help with solving a system of equations. Need to understand the rules to solve the... (answered by Alan3354)
could someone please help?
I need to solve each system of equations using guassian... (answered by solver91311)
Use substitution or elimination to solve each system of equations. Please explain.... (answered by jim_thompson5910)
Solve the system of equations by the method of elimination.
-x + 4y = -11
11x - y =... (answered by Boreal)
Use the elimination method to solve the system of equations.
x+6y=33... (answered by stanbon,MathTherapy)
use elimination to solve each system of equations
6s+5t=1... (answered by checkley75)
Use elimination to solve each system of equations.
13a+5b=-11
(answered by stanbon)
Use substitution or elimination to solve each system of equations.
2x + 5y= 16
5x -... (answered by mananth)