SOLUTION: Write a system of two equations in two unknowns for each problem. Solve each system by substitution. The width of a rectangualr painting is two -thirds of its length. If the per

Question 178257: Write a system of two equations in two unknowns for each problem. Solve each system by substitution.
The width of a rectangualr painting is two -thirds of its length. If the perimeter is 28ft, then what are the length and width?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The width of a rectangular painting is two-thirds of its length. If the perimeter is 28ft, then what are the length and width?
:
Write an equation for each statement;
:
"The width of a rectangular painting is two-thirds of its length.
W = L
:
" If the perimeter is 28ft,"
2L + 2W = 28
:
then what are the length and width?
:
Substitute L for W in the perimeter equation, Find L:
2L + 2(L) = 28
2L + L = 28
multiply eq by 3 to get rid of that annoying denominator, results:
6L + 4L = 3(28)
:
10L = 84
L=
L = 8.4 ft
:
Find W
(8.4) = 5.6 ft
:
:
Check solution:
2(8.4) + 2(5.6) =
16.8 + 11.2 = 28 ft
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