SOLUTION: Al will rent a car for the weekend. He can choose one of two payment plans. The first plan costs $51.98 for two days plus 15 cents per mile. The second plan costs $39.98 for two da

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Al will rent a car for the weekend. He can choose one of two payment plans. The first plan costs $51.98 for two days plus 15 cents per mile. The second plan costs $39.98 for two da      Log On


   

Question 177176: Al will rent a car for the weekend. He can choose one of two payment plans. The first plan costs $51.98 for two days plus 15 cents per mile. The second plan costs $39.98 for two days plus 20 cents per mile. How many miles does Al need to drive for the two plans to cost the same?

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let's write the cost equations (C) for both car rentals:
C%5B1%5D+=+51.98%2B0.15m where m = number of miles driven.
C%5B2%5D+=+39.98%2B0.20m
Since you need to know when the costs will be equal, set these two equations equal to each other.
51.98%2B0.15m+=+39.98%2B0.20m Now you can solve for m, the number of miles. Subtract 0.15m from both sides.
51.98+=+39.98%2B0.05m Now subtract 39.98 from both sides.
12+=+0.05m Finally, divide both sides by 0.05
240+=+m
So, Al must drive 240 miles for the costs of both plan to be the same.