SOLUTION: Mario's age is two years more than twice Nadia's age. In nine years the sum of their ages will be 2/3 of his.
How do I solve???
Algebra.Com
Question 175971: Mario's age is two years more than twice Nadia's age. In nine years the sum of their ages will be 2/3 of his.
How do I solve???
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I started to solve the problem and then realized that
it's impossible. There is no way that at any time
the sum of their ages can be less than one of their
ages. Was it copied wrong?
RELATED QUESTIONS
Lucas is 9 years older than three times his son’s age. In 14 years, the age of Lucas... (answered by josgarithmetic,MathTherapy)
Lucas is 9 years older than three times his son’s age. In 14 years, the age of Lucas... (answered by josgarithmetic)
Lucas is 9 years older than three times his son’s age. In 14 years, the age of Lucas... (answered by josgarithmetic,ikleyn)
Mon is 8 years younger than Ram. In two years, the age of Ram will be 2 less than twice... (answered by algebrahouse.com)
Joan 3 times as old as her sister. In 3 years, she will be two more than twice the age of (answered by ikleyn,josgarithmetic)
Ike’s age is three years more than twice his younger brother’s age. If the sum of their... (answered by rfer)
Matt is 4 years older than Todd. In 3 years. Twice matt’s Age will be 8 more than twice (answered by ikleyn)
The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three... (answered by josgarithmetic,MathTherapy)
The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three... (answered by josgarithmetic)