SOLUTION: Please help me solve this equation:
using a system of two equations.
The sum of a certain number and a second number is -42. The first number minus the second is 52. Find t
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Question 168849This question is from textbook Prentice Hall Algebra 2 with trigonometry
: Please help me solve this equation:
using a system of two equations.
The sum of a certain number and a second number is -42. The first number minus the second is 52. Find the numbers.
This question is from textbook Prentice Hall Algebra 2 with trigonometry
Found 2 solutions by Mathtut, jim_thompson5910:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
lets call the numbers a and b
:
a+b=-42...eq 1
a-b=52....eq 2
using the elimination method to solve means we try to eliminate one of the variables and we can do that just by adding the 2 equation together(the b terms cancel out.
:
we end up with 2a=10---> divide by 2 and
:
to find b just plug a's value into either equation
:
5-b=52--->subtract 5 from each side and divide by -1
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"sum of a certain number and a second number is -42" ---->
"first number minus the second is 52" ---->
So we have the system of equations:
Add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:
Group like terms.
Combine like terms. Notice how the y terms cancel out.
Simplify.
Divide both sides by to isolate .
Reduce.
------------------------------------------------------------------
Now go back to the first equation.
Plug in .
Multiply.
Subtract from both sides.
Combine like terms on the right side.
So our answer is and .
Which form the ordered pair )
.
This means that the system is consistent and independent.
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