SOLUTION: solve using any methord
x/3-y/2=3
x/2+y/3=7/3
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Question 168735: solve using any methord
x/3-y/2=3
x/2+y/3=7/3
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the first equation.
Multiply EVERY term by the LCD to clear the fractions.
Multiply and simplify
---------------------------------
Move onto the second equation.
Multiply EVERY term by the LCD to clear the fractions.
Multiply and simplify
-----------------------------
So we have the system of equations:
Multiply the both sides of the first equation by 2.
Distribute and multiply.
Multiply the both sides of the second equation by 3.
Distribute and multiply.
So we have the new system of equations:
Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:
Group like terms.
Combine like terms. Notice how the y terms cancel out.
Simplify.
Divide both sides by to isolate .
Reduce.
------------------------------------------------------------------
Now go back to the first equation.
Plug in .
Multiply.
Subtract from both sides.
Combine like terms on the right side.
Divide both sides by to isolate .
Reduce.
So our answer is and .
Which form the ordered pair )
.
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