SOLUTION: There are two numbers whose sum is 50. Three times the first is five more than twice the second. What are the numbers?
Please DO answer quickly.
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Question 165268: There are two numbers whose sum is 50. Three times the first is five more than twice the second. What are the numbers?
Please DO answer quickly.
Found 2 solutions by jim_thompson5910, Mathtut:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"There are two numbers whose sum is 50" --->
"Three times the first is five more than twice the second" --->
Start with the first equation.
Subtract x from both sides.
Move onto the second equation
Plug in
Distribute.
Combine like terms on the right side.
Add to both sides.
Combine like terms on the left side.
Divide both sides by to isolate .
Reduce.
Go back to the previously isolated equation
Plug in
Subtract
----------------------------------------------------------------------
Answer:
So the solutions are and which form the ordered pair (21,29)
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
call the numbers a and b. a+b=50 so a=50-b (3 times a)(3a)=5+(2 times b)(2b)
re written as 3a=5+2b. Now substituting a's value from first equation into 2nd equation we get 3(50-b)= 5+2b or 150-3b=5+2b adding 3b and subtracting 5 from each side we get 5b=145 so b =29 so since a=50-b(29) the a =21
answer: a=21 and b=29
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