SOLUTION: a motorcycle breaks down and the rider must walk the rest of the way to work.The motorcyle was riden 45mph and the rider walks at the speed of 6mph. the distance from home to work
Algebra.Com
Question 165249: a motorcycle breaks down and the rider must walk the rest of the way to work.The motorcyle was riden 45mph and the rider walks at the speed of 6mph. the distance from home to work is 25mi.And the total of the trip was 2hrs. How far did the motorcycle go before it broke down?
Question how do you set this system of equation up?
ISBN-10 0-321-33191-5
Chapter 13
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
45x+6(2-x)=25
45x+12-6x=25
39x=25-12
39x=13
x=13/39
x=.333 hours for the 45 mph trip.
45*.333=15 miles is the motorcycle trip distance.
Proof:
45*.333+6(2-.333)=25
15+6(1.667)=25
15+10=25
25=25
RELATED QUESTIONS
a motorcycle breaks down and the rider must walk the rest of the way to work.The... (answered by checkley77,vleith)
A motorcycle breaks down and the rider must walk the rest of the way to work. The... (answered by ankor@dixie-net.com)
A motorcycle breaks down and the rider must walk the rest of the way to work. The... (answered by stanbon)
A motorcycle breaks down and the rider must walk the rest of the way to work. The... (answered by rwm)
A motorcycle breaks down and the rider has to walk the rest of the way to work. The... (answered by ankor@dixie-net.com)
a motorcycle breaks down and the rider has to walk the rest of the way to work.... (answered by ankor@dixie-net.com)
A motorcycle breaks down and the rider must walk the rest of the way to work. The... (answered by stanbon)
A motorcycle breaks down and the rider has to walk the rest of the way to work. The... (answered by josmiceli)
a motorcycle breaks down and the rider has to walk the rest of the way to work.the... (answered by mayank)