SOLUTION: solve by substitution: {{{sqrt(x)-y=0}}} {{{2x+y=3}}}

Question 164983: solve by substitution:

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve by substitution:

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square both sides
x = y^2
Sub into the 2nd eqn

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=25 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1, -1.5. Here's your graph:

These are the values for y - the solver always uses x as the variable.
The solver has a problem sometimes.
It's (y-1)*(2y+3), the answers shown are correct.
So for y = 1, x = 1
For y = -3/2, x = 9/4

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