SOLUTION: The second digit of a two digit no is 3 time of first digit. If the position of the digit is interchanged and added to original no the new no is 88. find the digits using only one

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Question 163114: The second digit of a two digit no is 3 time of first digit. If the position of the digit is interchanged and added to original no the new no is 88. find the digits using only one variables.
Answer by Fombitz(13828) About Me  (Show Source):
You can put this solution on YOUR website!
Let's let the first digit be A and the second digit be B.
The number can be represented as,
10%2AA%2BB
You also know that
1.B=3A
When you interchange the digits, the new number becomes,
10%2AB%2BA
And then you also know that
2.%2810%2AA%2BB%29%2B%2810%2AB%2BA%29=88
2.11A%2B11B=88
2.A%2BB=8
Plug the value for B from eq. 1 into eq. 2 and solve for A.
2.A%2B3A=8
4A=8
A=2
From eq. 1,
B=3%282%29=6
The original number is 26, the interchange number is 62.
As a check, add them together to get 88.
.
.
.
A=2
B=6