Questions on Algebra: Systems of Linear Equations answered by real tutors!

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Question 153208: how do you solve y= 1/3x - 3 and y= -2x + 4 algebraically?
this is the question;
Solve the above system of equations algebraically, use the elimination or substitution method.
PLEASE HELP!!!!: how do you solve y= 1/3x - 3 and y= -2x + 4 algebraically?
this is the question;
Solve the above system of equations algebraically, use the elimination or substitution method.
PLEASE HELP!!!!
Answer by jim_thompson5910(9368) About Me  (Show Source):
You can put this solution on YOUR website!
y= (1/3)x - 3 Start with the first equation.


-2x + 4= (1/3)x - 3 Plug in y= -2x + 4


3(-2x+4)=3((1/cross(3))x-3) Multiply both sides by the LCD 3 to clear any fractions.


-6x+12=x-9 Distribute and multiply.


-6x=x-9-12 Subtract 12 from both sides.


-6x-x=-9-12 Subtract x from both sides.


-7x=-9-12 Combine like terms on the left side.


-7x=-21 Combine like terms on the right side.


x=(-21)/(-7) Divide both sides by -7 to isolate x.


x=3 Reduce. This is the first part of our answer.


y= -2x + 4 Move onto the second equation


y= -2(3) + 4 Plug in x=3


y= -2 Simplify. This is the second part of our answer.


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Answer:

So the solutions are x=3 and y= -2 which form the ordered pair (3,-2)