SOLUTION: Problem: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins w
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Question 149098: Problem: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
:
Write an equation for each statement
"Joe has a collection of nickels and dimes that is worth $5.65."
.05n + .10d = 5.65
:
"If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45."
.05(n+8) + .10(2d) = 10.45
:
.05n + .4 + .20d = 10.85
.05n + .20d = 10.45 - .40
.05n + .20d = 10.05
:
Subtract the 1st equation from the above equation
.05n + .20d = 10.05
.05n + .10d = 5.65
----------------------subtracting eliminates n, find d
0n + .10d = 4.40
d =
d = 44 dimes
;
:
You can calculate the number of nickels using the 1st equation, then
Check the solutions in the 2nd equation
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