SOLUTION: The perimter of a rectangle is 66 inches. The length exceeds the width by 27 inches. Find the length and width. The length is ?? inches The width is ?? inches Please HELP.

Question 147955: The perimter of a rectangle is 66 inches. The length exceeds the width by 27 inches. Find the length and width.
The length is ?? inches
The width is ?? inches
Please HELP.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x=length and y=width

Remember, the perimeter formula is . Since the perimeter is 66 inches, this means that . So the equation is now .

Also, because the "length exceeds the width by 27 inches", this tells us that

Start with the first equation.

Plug in

Distribute.

Combine like terms on the right side.

Subtract from both sides.

Subtract from both sides.

Combine like terms on the right side.

Divide both sides by to isolate .

Reduce.

So the width is 3 inches.

Go back to the second equation.

Plug in

Add.

So the length is 30 inches

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Answer:

So the length is 30 inches and the width is 3 inches
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