# SOLUTION: Hi, I dont know what Im doing wrong I need help please. Here is the question: One year ago you invested \$4300 into three accounts that earn 3.25%, 4%, and 5.75% annual interest. T

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Hi, I dont know what Im doing wrong I need help please. Here is the question: One year ago you invested \$4300 into three accounts that earn 3.25%, 4%, and 5.75% annual interest. T      Log On

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 Click here to see ALL problems on Linear-systems Question 147364: Hi, I dont know what Im doing wrong I need help please. Here is the question: One year ago you invested \$4300 into three accounts that earn 3.25%, 4%, and 5.75% annual interest. The interest you earned after one year is \$193. You remembered you invested three times as much in the 4% account than you did the 3.25% account. How much did you invest in each type of account? This is what i have so far, I dont think its right. x + y + Z = 4300 325x + 400Y + 575z = 19300 Y=3x x + (3x) + Z = 4300 4x + z = 4300 325x + 400 (3x) + z =19300 1525x +575z = 19300 (-575) 4x + z = 4300 (-575) -2300x - 575z =-2472500 1525x + 575z = 19300 -775x = -2453200 x=3165.4 then when I do 3 times x to get y it doesnt fit with the total of 4300. I dont know please help me thank you.Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!Hi, I dont know what Im doing wrong I need help please. Here is the question: One year ago you invested \$4300 into three accounts that earn 3.25%, 4%, and 5.75% annual interest. The interest you earned after one year is \$193. You remembered you invested three times as much in the 4% account than you did the 3.25% account. How much did you invest in each type of account? This is what i have so far, I dont think its right. x + y + Z = 4300 0.0325x + 0.0400Y + 0.0575z = 193 Y=3x ----------- x + y + z = 4300 325x + 400y + 575z = 1930000 3x - y + 0 = 0 ------------ Solve the system of equations by any method to get: x = 700 y = 2100 z = 1500 =========== Cheers, Stan H.