SOLUTION: Solve the system of equations by graphing. Then classify the system as consistent or inconsistent and the equations as dependent or independent. x+y=7 x-y=-3

Question 145838: Solve the system of equations by graphing. Then classify the system as consistent or inconsistent and the equations as dependent or independent.

x+y=7
x-y=-3
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given system of equations:

In order to graph these equations, we need to solve for y for each equation.

So let's solve for y on the first equation

Start with the given equation

Subtract from both sides

Rearrange the equation

Now lets graph (note: if you need help with graphing, check out this solver)

Graph of

So let's solve for y on the second equation

Start with the given equation

Subtract from both sides

Rearrange the equation

Divide both sides by

Break up the fraction

Reduce

Now lets add the graph of to our first plot to get:

Graph of (red) and (green)

From the graph, we can see that the two lines intersect at the point (2,5)

So the system is consistent and independent
RELATED QUESTIONS
Solve the system of equations by graphing. Then classify the system as consistent or... (answered by jim_thompson5910)

Solve the system of equations by graphing. Then classify the system as consistent or... (answered by oscargut)

Solve the systems of equations by graphing. Then classify the system as consistent or... (answered by jim_thompson5910)

Solve the systems of equations by graphing. Then classify the system as consistent or... (answered by Fombitz)

solve the system of equations by graphing. Then classify the system as consistent or... (answered by Alan3354)

Solve the system of equations by graphing. Then classify the system as consistent or... (answered by stanbon)

Solve the system of equations by graphing. Then classify the system as consistent or... (answered by Gogonati)

solve the system of equation by graphing. then classify the system as consistent aor... (answered by nabla)