# SOLUTION: How do I solve this system of equations by using multiplication with the addition method? 1/5(x+2y)=-2 x/4-3y/2=15/2

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 Click here to see ALL problems on Linear-systems Question 140983This question is from textbook Prentice Hall Algebra 1 : How do I solve this system of equations by using multiplication with the addition method? 1/5(x+2y)=-2 x/4-3y/2=15/2This question is from textbook Prentice Hall Algebra 1 Answer by ankor@dixie-net.com(15649)   (Show Source): You can put this solution on YOUR website!How do I solve this system of equations by using multiplication with the addition method? : 1/5(x+2y) = -2 Multiply by 5 to get rid of the denominator x + 2y = 5(-2) x + 2y = -10 : - = Multiply equation by 4 to get rid of the denominator, resulting: x - 2(3y) = 2(15) x - 6y = 30 : Multiply the 1st equation by -1 and add to the above equation -x - 2y = +10 +x - 6y = +30 ----------------- 0x - 8y = +40 y = y = -5 : Find x using x - 6y = 30: x - 6(-5) = 30 x + 30 = 30 x = 0 ; : Check solution using the 1st original equation: 1/5(x + 2y) = -2 1/5(0 + 2(-5) = 1/5 * -10 = -2