SOLUTION: Could someone please show me step-by-step how to solve this? Thank You for your help. Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Could someone please show me step-by-step how to solve this? Thank You for your help. Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35      Log On

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Question 137354: Could someone please show me step-by-step how to solve this? Thank You for your help.
Solve the system.
4x^2-4y^2=20
3x^2+2y^2=35
Answer by stanbon(57214) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the system.
4x^2-4y^2=20
3x^2+2y^2=35
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Multiply the 2nd equation by thru by 2 to get:
6x^2+4y^2=50
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Add that to the 1st equation to get:
10x^2 = 70
x = +/-sqrt7
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Substitute into 4x^2-4y^2=20 to solve for "y":
4*7 -4y^2 = 20
4y^2 = 8
y = +/-sqrt2
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Cheers,
Stan H.