SOLUTION: Could someone please show me step-by-step how to solve this? Thank You for your help. Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Could someone please show me step-by-step how to solve this? Thank You for your help. Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35      Log On

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 Click here to see ALL problems on Linear-systems Question 137354: Could someone please show me step-by-step how to solve this? Thank You for your help. Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35Answer by stanbon(57214)   (Show Source): You can put this solution on YOUR website!Solve the system. 4x^2-4y^2=20 3x^2+2y^2=35 -------------------- Multiply the 2nd equation by thru by 2 to get: 6x^2+4y^2=50 --------- Add that to the 1st equation to get: 10x^2 = 70 x = +/-sqrt7 ------------- Substitute into 4x^2-4y^2=20 to solve for "y": 4*7 -4y^2 = 20 4y^2 = 8 y = +/-sqrt2 =============== Cheers, Stan H.