# SOLUTION: Could someone help me understand how to solve the problem posted...especially how the variable or unknown will be removed from the denominator. Any help would be greatly appreciate

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Could someone help me understand how to solve the problem posted...especially how the variable or unknown will be removed from the denominator. Any help would be greatly appreciate      Log On

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 Click here to see ALL problems on Linear-systems Question 137256: Could someone help me understand how to solve the problem posted...especially how the variable or unknown will be removed from the denominator. Any help would be greatly appreciated. Question: Solve the following system: 5/3a - 7 = -2/5b 7/6a - 1/10b = 3 Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!Solve the following system: (5/3)a - 7 = (-2/5)b (7/6)a - (1/10)b = 3 ------------ Multiply thru the 1st equation by (1/2) to get: (5/6)a - (7/2) = (-2/10)b Rearrange to get: A) (5/6)a + (2/10)b = (7/2) Multiply 2nd equation by 2 to get: B) (14/6)a - (2/10)b = 6 ---------------------- Add equation A to equation B to solve for "a": (19/6)a = 19/2 (1/6)a = 1/2 a = 3 ----------- Substitute that into (7/6)a - (1/10)b = 3 to solve for "b" (7/6)3 - (1/10)b = 3 (-1/10)b = (-1/6)3 b = (-10)(-1/2) b = 5 -------------- Final answer: a=3; b=5 ================================ Cheers, Stan H.