# SOLUTION: im not quit sure what cat. this question would go under so i tried to find the closes one...i apologize if it is off topic... a 40 ft. board is to be cut into two peices. The LO

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: im not quit sure what cat. this question would go under so i tried to find the closes one...i apologize if it is off topic... a 40 ft. board is to be cut into two peices. The LO      Log On

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 Question 13544: im not quit sure what cat. this question would go under so i tried to find the closes one...i apologize if it is off topic... a 40 ft. board is to be cut into two peices. The LONGER PIECE is to be 7 feet longer than twice the SHORTER peice. How long is each peice? let x= shorter peice ___=the longer peice equation:Answer by LilSkittleMd(119)   (Show Source): You can put this solution on YOUR website!x=shorter piece y=longer piece The 40 ft board is to be cut into 2 pieces,which is the equation: x+y=40 The Longer piece is 7 feet longer than twice the shorter piece, its equation is: y=7+2x Then you substitute the y= equation into the x+y equation: x+7+2x=40 (add together the x's, subtract 7 from 40) 3x=33 (divide by 3 to isolate x) x=11 Then plug x into either equation y=7+2(11) y=7+22 y=29 The shorter piece is 11 feet and the longer piece is 29 feet. Check: 11+29=40 40=40 29=7+2(11) 29=7+22 29=29