# SOLUTION: without graphing, determine which of the following 3 points: P1 = (8,6) P2 = (2,5) P3 = (4,1) are part of the graph of the following system: y - 10x <= 0 2y - 3x >= 0 y + x

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: without graphing, determine which of the following 3 points: P1 = (8,6) P2 = (2,5) P3 = (4,1) are part of the graph of the following system: y - 10x <= 0 2y - 3x >= 0 y + x       Log On

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 Click here to see ALL problems on Linear-systems Question 128898: without graphing, determine which of the following 3 points: P1 = (8,6) P2 = (2,5) P3 = (4,1) are part of the graph of the following system: y - 10x <= 0 2y - 3x >= 0 y + x <= 15Answer by solver91311(16897)   (Show Source): You can put this solution on YOUR website!without graphing, determine which of the following 3 points: P1 = (8,6) P2 = (2,5) P3 = (4,1) are part of the graph of the following system: y - 10x <= 0 2y - 3x >= 0 y + x <= 15 Just substitute the values for the x- and y-coordinates into the inequalities. If all three statements are true for a point, then the point is in the solution set, but if any one of the statements is false, the point is not in the solution set. 6 - 10(8) <= 0: True 2(6)-3(8) >= 0: False. Don't bother checking the third inequality, the point P1(8,6) is not in the solution set. Follow the same procedure for the other two points.