SOLUTION: I am an older student in Algebra and it is sooooooo confusing. I am having trouble with order of operations. Can you help me with this problem?: 7(3x-2)+5=6(2x-1)+24 this is what

Question 12840: I am an older student in Algebra and it is sooooooo confusing. I am having trouble with order of operations. Can you help me with this problem?:
7(3x-2)+5=6(2x-1)+24
this is what I have tried:
21x-14+5=12x-6+24
21x-9=12x+18
9x=-9+18
9x=9
x=1
But it's not right when I check it-but I may be doing that wrong also. Thank you for any help!
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
You were on the right track till you you got to the step of subtracting the 9 from both sides.
You have 21x-9=12x+18
Which actually is 21x+(-9)=12x+18
Remember to get rid of the 9 and make it a zero you need to add a POSITIVE 9 to both sides.
So you get: 21x-9+9=12x+18+9
This cancels out the 9 from the left side;
21x=12x+18+9;
21x-12x=27
9x=27
x=3
Hope this helps you with your algebra, it really isn't that difficult.
=)
RELATED QUESTIONS
Hi, my names Marlene and I am having trouble with this problem in Pre-Algebra. It is... (answered by rfer,MathTherapy)

One of the major problems I am having with algebra, Geometry,ect. Is that I am having... (answered by vleith)

I have to write the phrases in my book as an algebraic expression and simplify if... (answered by ReadingBoosters)

How do you solve any type of q- equation? I am starting on these, but am having some... (answered by stanbon)

Hi! I'm an algebra one student and I am having trouble with word problems. My teacher has (answered by richard1234)

I am an older student in math 27 (if that means anything) and I am failing the class. I... (answered by Earlsdon,tayjay,pwac)

I am having trouble with the order of operations with this equation: "Evaluate each... (answered by scott8148)

I am taking an Algebra course in school right now and I am having a bit of trouble with... (answered by oberobic)

I am having trouble with this problem. It is 3-2(x-3)=5+(x-2). Can you... (answered by rfer)