SOLUTION: 14. Geometry. The perimeter of an isosceles triangle is 37 in. The lengths of the two
equal legs are 6 in. less than 3 times the length of the base. Find the lengths of the
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Question 123630: 14. Geometry. The perimeter of an isosceles triangle is 37 in. The lengths of the two
equal legs are 6 in. less than 3 times the length of the base. Find the lengths of the
three sides.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x=length of equal leg, y= length of base
Since the perimeter is equal to the sum of all three sides, the perimeter is
which simplifies to
Since the " lengths of the two equal legs are 6 in. less than 3 times the length of the base", this means
Start with the given formula
Plug in and
Distribute
Combine like terms on the right side
Subtract 37 from both sides
Subtract 7y from both sides
Combine like terms on the right side
Divide both sides by -7 to isolate y
Divide
Since we know that , we can plug this into to find x
Start with the given equation
Plug in
Multiply
Subtract
So the length of the equal leg is 15 and the length of the base is 7
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