SOLUTION: ELIMINATION: How do you figure this out using ELIMINATION: 5x + 3y = 1.5 -8x - 2y = 20

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Question 122872: ELIMINATION: How do you figure this out using ELIMINATION:
5x + 3y = 1.5
-8x - 2y = 20

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the first equation

Multiply both sides by 10 to move the decimal on each number 1 time. This will make every number a whole number.

Distribute and multiply



So our system is now:






Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.





In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for , we would have to eliminate (or vice versa).


So lets eliminate . In order to do that, we need to have both coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.



So to make the coefficients equal in magnitude but opposite in sign, we need to multiply both coefficients by some number to get them to an common number. So if we wanted to get and to some equal number, we could try to get them to the LCM.



Since the LCM of and is , we need to multiply both sides of the top equation by and multiply both sides of the bottom equation by like this:




Multiply the top equation (both sides) by
Multiply the bottom equation (both sides) by




Distribute and multiply





Now add the equations together. In order to add 2 equations, group like terms and combine them



Combine like terms and simplify



Notice how the x terms cancel out




Simplify




Divide both sides by to isolate y




Reduce



Now plug this answer into the top equation to solve for x

Start with the first equation



Plug in



Subtract 240 from both sides


Combine like terms on the right side


Divide both sides by 50 to isolate x



Reduce




So our answer is
and



which also looks like




Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of (red) and (green) and the intersection of the lines (blue circle).



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