SOLUTION: Filling a swimming pool Two hoses are used to fill a swiming pool. If the first runs for 3h and the second for 2h, the pool will contain 1190 L of water. But if the first one is

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Filling a swimming pool Two hoses are used to fill a swiming pool. If the first runs for 3h and the second for 2h, the pool will contain 1190 L of water. But if the first one is      Log On


   



Question 122772: Filling a swimming pool
Two hoses are used to fill a swiming pool. If the first runs for 3h and the second for 2h, the pool will contain 1190 L of water. But if the first one is used for 2h and the second one for 3h, the pool will contain 1260 L.
a)represent this situation by a system of equations.
b)what is the flow rate of each hose?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Two hoses are used to fill a swiming pool. If the first runs for 3h and the second for 2h, the pool will contain 1190 L of water. But if the first one is used for 2h and the second one for 3h, the pool will contain 1260 L.
:
Let x = 1st hose flow rate liters/hr
Let y = 2nd hose flow rate
:
a)represent this situation by a system of equations.
:
3x + 2y = 1190
2x + 3y = 1260
:
b)what is the flow rate of each hose?
We will use elimination here
Multiply the 1st equation by 3, and the 2nd equation by 2;
9x + 6y = 3570
4x + 6y = 2520
----------------- subtracting eliminates y; find x
5x + 0y = 1050
x = 1050%2F5
x = 210 liter/hr flow rate
:
Find y:
3x + 2y = 1190
3(210) + 2y = 1190
630 + 3y = 1190
2y = 1190 - 630
y = 560%2F2
y = 280 liter/hr flow rate
:
:
Check solution in 2nd equation
2(210) + 3(280) =
420 + 840 = 1260